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Pls helpme!!!!
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TOPIC: Pls helpme!!!!
#2621
Pls helpme!!!! 1 Year, 9 Months ago Karma: 0
1)Ali and May bought some money for shopping.The ratio of Ali's money to May's money is 3:8.The ration of their spending was 3:5.Ali spent 3/4 of his money and mary had $170 left.how much did Ali have at first?

2)Beads were used to string 3 necklaces A,B and C.40% of the the number of the beads on necklace A is equal to 25% of the beads of the beads on necklace B.the number of beads on necklace in C is 1/3 of the beads on neklace B.
a) Express the number of beads on necklace C as a ration to the number of beads on necklace A.
b)If half the beads on necklace B are removed and added onto the necklace C, there will be 80 beads on ecklace C.how many beads are there altogether?
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#2629
Pls help me! 1 Year, 9 Months ago Karma: 43
pin wrote:
1)Ali and May bought some money for shopping.The ratio of Ali's money to May's money is 3:8.The ratio of their spending was 3:5.Ali spent 3/4 of his money and Mary had $170 left.how much did Ali have at first?Ratio of money
A : M
3 : 8
12 : 32

Ratio of spending
3 : 5
9 : 15

Ali spent 3/4 of his money means (12-9) = 3 units.
Mary had $170 left -> (32-15)units = 17 units.

17 units = $170
12 units = $120

At first, Ali had $120
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#2630
Pls helpme!!!! 1 Year, 9 Months ago Karma: 43
pin wrote:
2)Beads were used to string 3 necklaces A,B and C.40% of the the number of the beads on necklace A is equal to 25% of the beads of the beads on necklace B.The number of beads on necklace in C is 1/3 of the beads on necklace B.
a) Express the number of beads on necklace C as a ratio to the number of beads on necklace A.
b)If half the beads on necklace B are removed and added onto the necklace C, there will be 80 beads on necklace C.How many beads are there altogether?
40% = 2/5
25% = 1/4

2/5 of A = 1/4 of B
2/5 of A = 2/8 of B

A : B
5 : 8
15: 24

C : B
1 : 3
8 : 24

A : B : C
15 : 24 : 8

(a)Number of beads on necklace C as a ratio to the number of beads on necklace A = 8:15

1/2x24u = 12u
8u+12u = 20u

20u = 80
u = 4

A+B+C = (15+12+20)u = 47u = 47x4 = 188
b)There are 188 beads altogether.
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#2632
Re: Pls helpme!!!! 1 Year, 9 Months ago Karma: 0
thank you Perseverance...
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