Welcome, Guest
Username: Password: Remember me
  • Page:
  • 1

TOPIC: Maths solution P5

Maths solution P5 3 years 10 months ago #1

Blue pins are sold in packets of 8. Red pins are sold in packets of 6. Every packet of pins costs \(2. Mrs Chan bought the same number of blue and red pins. With \)100, how many packets of pins could she have bought at the most?

Pls provide solution step-by-step with explanation, thank you.
  • ssng
  • ssng's Avatar
  • OFFLINE
  • Karma: 0
The administrator has disabled public write access.

Re:Maths solution P5 3 years 10 months ago #2

ssng wrote:
Blue pins are sold in packets of 8. Red pins are sold in packets of 6. Every packet of pins costs \(2. Mrs Chan bought the same number of blue and red pins. With \)100, how many packets of pins could she have bought at the most?

Pls provide solution step-by-step with explanation, thank you.
Hi ssng

Since Mrs Chan bought the same number of blue and red pins, we have to get the lowest common multiple of 8 and 6

Blue pins --- 24 pins --- 24/8 --- 3 packets
red pins --- 24 pins --- 24/6 ---- 4 packets

3 packets of blue pins an 4 packets of red pins --- 7 packets will form 1 group
1 group costs ---- \(2 x 7 = \)14

No. of group ---- \(100/\)14 = 7 groups Remainder $2(discard)

packets of pins she could have bought at most --- 7 x 7 = 49 packets (answer)

Hope this helps
The administrator has disabled public write access.
  • Page:
  • 1

About Us | Contact Us | Join Us | Terms of Use | Privacy Policy | Sitemap | Sign Up

Copyright 2008 onSponge Pte Ltd. All rights reserved

Protected by R Antispam