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TOPIC: Maths solution P5

Maths solution P5 6 years 1 month ago #1

  • ssng
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Blue pins are sold in packets of 8. Red pins are sold in packets of 6. Every packet of pins costs $2. Mrs Chan bought the same number of blue and red pins. With $100, how many packets of pins could she have bought at the most?

Pls provide solution step-by-step with explanation, thank you.
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Re:Maths solution P5 6 years 1 month ago #2

  • teresa
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ssng wrote:
Blue pins are sold in packets of 8. Red pins are sold in packets of 6. Every packet of pins costs $2. Mrs Chan bought the same number of blue and red pins. With $100, how many packets of pins could she have bought at the most?

Pls provide solution step-by-step with explanation, thank you.
Hi ssng

Since Mrs Chan bought the same number of blue and red pins, we have to get the lowest common multiple of 8 and 6

Blue pins --- 24 pins --- 24/8 --- 3 packets
red pins --- 24 pins --- 24/6 ---- 4 packets

3 packets of blue pins an 4 packets of red pins --- 7 packets will form 1 group
1 group costs ---- $2 x 7 = $14

No. of group ---- $100/$14 = 7 groups Remainder $2(discard)

packets of pins she could have bought at most --- 7 x 7 = 49 packets (answer)

Hope this helps
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