1)Three girls A,B and C had a total of 1980 beads.Some exchanges were then made.First, A gave B as many beads as B had.After that,B gave 1/3 of whatever she had then to C.Finally, c gave whatever she had to A.As a result,they each had the same number of beads.How many beads did A have at first?

2)Becky and Ramli shared a packet of sweets equally.Becky packed the sweets she had equally into 3 packets.Ramli packed the sweets he had into 4 packets.There was a total of 77 sweets in 2 packets of sweets from Becky and 1 packet of sweets from Ramli.Find the total number of sweets in the original packet?

3)A,B and C shared a sum of money.A receives 40% of the sum of money.B receives 15% less than what A receives.C receives $287 less than A.
a) What percentage of the sum of money is C's share?
b) How much is A's share?





I m very very weak in math.......

Wow. So many questions
No LAH. Not so hard. You want to try and show your working for question 1.
What is the difficulty with this problem
Let's interact on this

oops. offline now. Fill In the Blanks

1)A picture 7cm by 9cm is mounted on a rectangular cardboard leaving a border of 1 1/2cm all round it.Express the area of the border as a fraction of the area of the picture.Give your answer in the simplest form.

Width of Cardboard = 7 + 1 1/2 + 1 1/2 = _____
Length of Cardboard = 9 + 1 1/2 + 1 1/2 = ______
Are of Cardboard = ____
Area of Picture = 7 x 9 = ____
Area of Border = Area of Cardboard - Area of Picture =____

Area of Border
Area of Picture <---- Answer

2)Three girls A,B and C had a total of 1980 beads.Some exchanges were then made.First, A gave B as many beads as B had.After that,B gave 1/3 of whatever she had then to C.Finally, C gave whatever she had to A. As a result,they each had the same number of beads.How many beads did A have at first?

"Finally, C gave whatever she had to A. As a result,they each had the same number of beads."

Eh. Cannot be LAH. If C gave whatever she had to A. She AIN't GOT NUTHIN'.
And A have a whole LOT
I think better change the question a bit.

2)Three girls A,B and C had a total of 1980 beads.Some exchanges were then made.First, A gave B as many beads as B had.After that,B gave 1/3 of whatever she had then to C.Finally, C gave, whatever A had, to A. As a result,they each the same number of beads.How many beads did A have at first?

can't change.......the question is like that.....

Hi Pin,

Let me ask you a question.

If C gave whatever she had to A.

How many beads would C be left with?

You need to answer this.

If John had 10 beads.
And John gave whatever he had to Ben.
How many beads would John be left with ?

0 left

So now we worked out that C had ZERO left after Giving whatever he had to A.

After this, they each had the same number of beads.

So, I repeat if C had ZERO and A had the same number of beads, how many beads would A have?

If C had ZERO beads and B had the same number of bead, how many beads would B have?

C -> 0 beads
B -> ______
A -> ______

Reynold wrote:
So now we worked out that C had ZERO left after Giving whatever he had to A.

After this, they each had the same number of beads.

So, I repeat if C had ZERO and A had the same number of beads, how many beads would A have?

If C had ZERO beads and B had the same number of bead, how many beads would B have?

C -> 0 beads
B -> ___0___
A -> ____0__ .....