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Jennifer Tan YP wrote:
Seems like a simple question but it became a curve ball for me! Pls help!
This is a 5-mark question from Nanyang 2009 P5 SA2 paper 2 Q17. Since it's a 5-mark question, it's not a simple question but also not a difficult one.What you have to do is to accept Working backwards strategy.
Jennifer Tan YP wrote:
Jolene and Penny had a sum of money. Jolene gave Penny 0.4 of her money. Penny then gave Jolene 1/2 of her money. In the end, Jolene had three times the amount of money that Penny had. If Jolene gave Penny $125 more than what Penny gave Jolene, how much moeny did JOlene have at first?
End
Jolene: 3u
Penny: u
Before
Jolene: 2u
Penny: 2u
At first
Jolene: 2ux5/3 = 10u/3
Penny: 2u/3
Jolene gave Penny-> 4u/3
Penny gave Jolene-> u
4u/3-u -> $125
u/3-> $125
u-> $125x3 = $375
At first, amount of money that Jolene had = 10u/3 = 10/3x$375 = $1250
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