Hearty wrote:
Attached please find the diagram of the tanks.
Q18. The figure shows 2 completely-filled tanks being emptied of the water from 2 different taps.
The taps at Tank A and Tank B were turned on at 7a.m. and 8.30a.m. respectively, until both the tanks were completely empty. At 11 a.m., the water level in both the tanks was the same. At 12.30p.m., Tank B was completely empty and Tank A was only completely empty at 1 p.m. If the rate of flow of water from each tap was constant throughout, what was the height of Tank A?
Ans: 45cm
Refer to
Observer's solution
or solution by "kancheongmum" in KSP forum:
Tank A emptied in 6 hrs --- 1 hour emptied 1/6 tank
Tank B emptied in 4 hrs --- 1 hour emptied 1/4 tank
Tank A in 4 hrs and Tank B in 2.5 hrs will reach the same height.
That means remaining tank to emptied
Tank A === 1 - (1/6 x 4) --- 1/3 tank
Tank B === 1 - (1/4 x 2.5) --- 3/8 tank
1/3 of height of Tank A is equal to 3/8 of height of Tank B
1/3 ---- 3/9
Height of Tank A 9u
Height of Tank B 8u
9u - 8u = 1u --- 5cm
Height of Tank A is 9 x 5 =
45cm
or solution by
tianzhu dated Fri Sep 10, 2010 7:29 am
